They are going!!!!!
1 Jessica Dubé / Bryce Davison 62.87+135.40=198.27
2 Anabelle Langlois / Cody Hay 65.47+117.95=183.42
3 Meagan Duhamel / Craig Buntin 62.38+109.80=172.18
4 Mylène Brodeur / John Mattatall 60.33+106.68=167.01
5 Kirsten Moore-Towers / Dylan Moscovitch 54.46+105.67=160.13
6 Paige Lawrence / Rudi Swiegers 58.22+99.34=157.56
7 Kaleigh Hole / Adam Johnson 46.00+97.20=143.20
8 Anne-Marie Giroux / Eric Radford 48.75+89.51=138.26
9 Brittany Jones / Kurtis Gaskell 49.11+84.52=133.63
10 Monica Pisotta / Michael Stewart 44.79+81.38=126.17
11 Jade-Savannah Godin / Andrew Evans 46.26+79.87=126.13
12 Noemie Arseneault / Simon-Pierre Côté 42.35+73.83=116.18
Langlois/Hays skated all right. I think they did enough, but it'll be close. As you mentioned, D/B are rougher - L/H have quite a clean line.
117.95/183.42; 2nd place.
Yay!!! Cody gets to skate in the Olympics in his hometown!
By the way, not crazy about Jessical Dube's hair style...makes her look so old....
I'm a ball of mess right now, feeling devastated for D/B and estatic for L/H. I've been rooting for Langlois for a very long time, I am glad that she gets to go to the Olympics again!
D/D had a very beautiful moment today, very much like sale/pelletier Congratulations! If they have this moment again in Vancouver, they may medal.
What does C or S mean in the protocols behind the jumps?
snowflake, I guess I just didn't love them the way I had hoped to post-
"Fascination." I think Cody fades into the background a bit too much. He's worked on his expression and the difference isn't as intense as say, the Ukranian pair V/M. But also keep in mind that Dube/Davison skated about as well as they did, if not better, at worlds 08 after I had pretty much written them off (yes, I'm an idiot. I also wrote of Chipeur and Joubert and Wier and my dog Skip....), so L/H were definitely a come down.
As for the "it'll be close" comment, well, refer back to the "I'm an idiot" part. I thought it would be closer.
For a combination, the base values of the jump are simply added together and you have the base value of the combo. For a sequence, the sum of the base values is than multiplied by a factor of 0.8, on the basis that sequences are easier than combos and shouldn't be worth as much.