But the data show also there are larger number of higher scores for Hanyu so his aggregate does not come entirely from a few extra large scores. He has more larger scores, especially after the high and low were discarded, which is why the the tendency is small.But in the aggregate, if the mean is larger than the median (the data is skewed to the right), this means that there is a tendency, however small in this example, for a few extra large scores have a greater effect on the mean than the few extra small ones.
But you can't prove that this is the case as announced.That's kind of a red herring. It is true but does not address the question of which skater was favored by the majority of the judges.
Anyway, the point is that it can, and does, happen in the CoP, that one skater is favored by a majority of judges but the other gets more CoP points, whatever the averaging procedure.
In this case Hanyu did win more higher ordinals than Joubert, seemingly even in just the PCS, which is why I debate your statement which can't be proven:I guess that's OK. That's how an add-up-the-points system works. It's different from 6.0, though. In 6.0, if you win the majority of first place ordinals, you win, period.
BTW, I was the one who complied the SSX10 vs PCS data per your suggestion.Thus the CoP. A majority of judges think that skater A was better, but skater B gets higher scores.