- Joined
- Jan 25, 2013
My issue is that PCS scores are impactful enough to negate technical performance. When clean skates (Murakami/Osmond SP, Ten's LP, Canadian pairs' LPs) are losing to technically poor performances by comparison (Kostner's SP, Chan's LP, Germans' LP), invariably the giant PCS advantage is at fault. In the SP it's less apparent because of the 0.8/1.0 factors, but in the FS with the PCS factored by 1.6/2.0, it's even more apparent.
Say a men's skater has a PCS advantage of 1.00 across all 5 categories over another skater in both the SP & FS -- that's 5 points higher PCS in the SP, and 10 points higher PCS in the LP. So automatically, the lesser PCS skater theoretically has a 15 point disadvantage (which they could make up if, say, they were allowed 2 extra jumping passes and did a 3A & 3Z) . Where skaters are separated by a 2.00 PCS advantage, that works out to a 30 point PCS disadvantage overall (which could be negated if the lesser skater was allowed 3 more jumping passes and executed 3 quads).
In the case of the ladies, a 1.00 PCS advantage across all categories equates to a 12 point disadvantage over SP+FS (so a lesser skater could make it up were she given two extra jumping passes and landed two 3Z's). For a 1.50 PCS advantage which equates to an 18 point disadvantage, the lesser skater would need to get three extra jumping passes and land all 3Z (or be given 2 extra jumping passes and land a 3Z+3T and 2A+3T) to make up the difference between them and the superior skater.
I know some skaters are vastly better than others, but that's a ridiculous discrepancy.
Say a men's skater has a PCS advantage of 1.00 across all 5 categories over another skater in both the SP & FS -- that's 5 points higher PCS in the SP, and 10 points higher PCS in the LP. So automatically, the lesser PCS skater theoretically has a 15 point disadvantage (which they could make up if, say, they were allowed 2 extra jumping passes and did a 3A & 3Z) . Where skaters are separated by a 2.00 PCS advantage, that works out to a 30 point PCS disadvantage overall (which could be negated if the lesser skater was allowed 3 more jumping passes and executed 3 quads).
In the case of the ladies, a 1.00 PCS advantage across all categories equates to a 12 point disadvantage over SP+FS (so a lesser skater could make it up were she given two extra jumping passes and landed two 3Z's). For a 1.50 PCS advantage which equates to an 18 point disadvantage, the lesser skater would need to get three extra jumping passes and land all 3Z (or be given 2 extra jumping passes and land a 3Z+3T and 2A+3T) to make up the difference between them and the superior skater.
I know some skaters are vastly better than others, but that's a ridiculous discrepancy.