Judging from the protocols and his layout today, a perfect Joubert would be aiming for:
4T+3T 13,800
4S 10,300
3A 8,200
FSSp3 2,600
4T 9,800
3Lz 6,600x
3Lo+3T 9,900x
CiSt3 3,300
3S 4,950x
3F 6,050x
CCoSp1 2,000
SlSt2 2,300
CSSp3 2,600
BaseValue 82,400
How reasonable is that???
That's a 3 quads LP. Happened 2 seasons ago at CoR, I believe. And never again since then? Besides, when was the last time Brian had a clean free?