And to know you are serious about that...

Hanyu is a better spinner than Chan, quite often Chan gets higher GOE on his spins than he should. They're really close in GOE, like it or not.
Of course I am serious because in my opinion of watching them both live and in front of a screen over the years, that has been correct as supported by their head-to-head results this year :
Spins GOE Comparison (eliminating any spins that had obvious downgrades or GOE errors for both skaters)
Skate Canada Int'l 2013
Hanyu
FCSp4 : 0.57 FCCoSp4 : 0.57
CSSp4 : 0.43 FCSSp4 : 0.93
CCoSp4 : 0.57 CCoSp4 : 0.86
Chan
CCSp3 : 0.71 FSSp4 : 1.07
FSSp4 : 0.93 CCSp4 : 0.79
CCoSp4 : 0.93
Hanyu' SP Average : 0.523 or +1.05
Chan's SP Average : 0.857 or +1.71
Hanyu's FS Average : 0.787 or +1.57
Chan's FS Average : 0.93 or +1.86
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TEB 2013
Hanyu
FCSp4 : 0.86 FCCoSp4 : 0.57
CSSp4 : 0.71 FCSSp4 : 0.93
CCoSp4 : 0.71 CCoSp4 : 0.79
Chan
CCSp3 : 0.64 FSSp4 : 1.00
FSSp4 : 1.07 CCSp4 : 0.86
CCoSp4 : 1.00 CCoSp3 : 0.79
Hanyu' SP Average : 0.76 or +1.52
Chan's SP Average : 0.90 or +1.80
Hanyu's FS Average : 0.763 or +1.53
Chan's FS Average : 0.883 or +1.77
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GPF 2013
Hanyu
FCSp4 : 1.00 FCCoSp4 : 1.00
CSSp4 : 0.93 FCSSp4 : 1.00
Chan
CCSp3 : 1.07 FSSp4 : 1.14
FSSp4 : 1.00 CCSp4 : 1.00
CCoSp4 : 0.86
Hanyu' SP Average : 0.965 or +1.93
Chan's SP Average : 0.977 or +1.95
Hanyu's FS Average : 1.00 or +2.00
Chan's FS Average : 1.07 or +2.14
Each skater has two of their spins removed from the 3 competitions combined due to obvious errors and/or downgrades to Lv1 such that they have equal number of data points, leaving only spins that do not have obvious errors, therefore more reflective of what they are capable of assuming no error.
Combined SP Average for Spins' GOE
Hanyu : 0.7225 (8 data points) or + 1.45
Chan : 0.9122 (9 data points) or + 1.82
Combined FS Average for Spins' GOE
Hanyu : 0.8313 (8 data points) or + 1.66
Chan : 1.0929 (7 data points) or + 2.19
Based on these data and facts, over 16 data points each this season, Chan has clearly outscored Hanyu in the GOE of Spins with one competition in each's respective home country and one in a 3rd country. Given that Spins have the least amount of GOE per element vs. Lv 4 Steps and most Triple and Quad jumps, looking at the raw GOE contribution on its own may not give us a full picture so I also translate into GOE Gradient to illustrate the differential, allowing a more direct comparison to other non-spin elements. In terms of GOE Gradient, Hanyu's Spins (16 data points), except those that had errors or downgrades to Lv1, averaged a GOE Gradient of +1.555. On the other hand, Chan's, also with 16 data points, had an average GOE Gradient of +1.982 - or about half of a point higher on average per spin element, not a subtle difference. Given that each competition, that is SP + FS have a total of 6 Spin elements, this GOE Gradient differential translate into an average difference of (1.982 - 1.555 ) X 0.50 X 6 = 1.28 On its own, 1.28 doesn't seem like a big deal in a competition, however, you combined it with the obvious GOE differential coming out of Step Sequences, suddenly, you are cutting that theoretical BV advantage of Hanyu's by about half, ignoring the GOE of jumps for now. Now, consider Hanyu has never actually landed a 4S this season, all of sudden that theoretical 6.3 advantage in BV smells like a pie in the sky. This is precisely why Chan will not and should not change his program by adding another Quad in lieu of the 2A - they should let Hanyu keep tumbling on that 4S and Chan should focus on skating a clean program - not missing the 3T at the end of the 4T, or messing up the final spin. Even in Japan, Chan still outscored Hanyu's GOE in spins - in fact, Hanyu botched 2 spins while in Japan but I courteously discounted those as one-off accidents that are not likely to repeat.
The bottom line is you are free to continue to believe that 1+1 = 3 or that Chan received unfairly high GOE in spins vs. Hanyu. It's difficult to understand however why there is such a strong consensus that among the 27 judges who saw them this season so far that the average of every segment, overall competition and all 3 competitions combined all pointed to Chan having a clear edge in the GOE of spins, even while in Japan. If we were to normalize the GOE Gradient of Spins as though they were jumps based on the GOE Gradient given, the difference would have been closer to 2 points of difference in the overall score. That's not a subtle difference by any definition knowing that this came from only 6 elements out of 20.
So yes, of course I am serious because facts support my assertions, as opposed to yours.